I'm trying to reverse engineer some FastLED code 1) so I don't have to

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1

I’m trying to reverse engineer some FastLED code 1) so I don’t have to ask as many questions and tie up everyone’s time, and 2) so I learn some code. Once again though, I’m at the office without a strip, trying to make productive use of my coffee break. So quick question…

if i =5 and j = 7 and you have…

leds[i+j] = CRGB::Red;

Will leds 5 and 7 both light up, or just led 12?

Thanks!

(If I get off work and to my leds before I get an answer, I’ll post my own answer for anyone else’s future reference.)

2

Just 12
If you want 5 and 7, then wrote two lines:
led[i] = …;
led[j] = …;

3

Thanks @Mike_Katchmar

4

Two separate lines as Mike wrote is probably the most clear as to what is going on, but this would also light both 5 and 7.
leds[i] = leds[j] = CRGB::Red;
//both pixels light red

And yet another alternative could be:
leds[i] = CRGB::Red;
leds[j] = leds[i];
//both pixels light red

Can be good to see other options to help understand someone else’s code.

5

Thanks some more @marmil !